This is impossible for vanadium, but is common for nonmetals such as sulfur: If electrons are added to an elemental species, its oxidation number becomes negative. The ion could be reduced back to elemental vanadium, with an oxidation state of zero. If the process is reversed, or electrons are added, the oxidation state decreases. Pb(NO₃)₂(aq) + NaCl(aq) → PbCl₂(s) + NaNO₃(aq)Ī) the Na⁺ ion will be attracted to the oxygen atom in water.ī) the Cl⁻ ion will be attracted to the oxygen atom in water.Ĭ) the Na⁺ ion will chemically bind to the water molecule.+ 2H^+ + e^-\]Įach time the vanadium is oxidized (and loses another electron), its oxidation state increases by 1. Balance the following chemical equation (if necessary): Write a balanced chemical equation based on the following description: iron metal reacts with oxygen gas to produce solid iron(III) oxideĥ. If no reaction occurs, write NR after the reaction arrow.Ĥ. Complete the balanced molecular chemical equation for the reaction below. If no reaction occurs, write NR after the reaction arrow.ģ. If no reaction occurs, write NR after the reaction arrow.Ģ. An acid-base reaction can be recognized because an acid is a compound that produces H+ ions in water and a base is a compound that produces OH- ions.ġ. A reaction in which one or more electrons are transferred from one atom to another is a redox reaction. Therefore, 8.37 g of Ca3(PO4)2 would be needed to form 4.30 g of CaSiO3.ġb) A reaction in which two solutions are mixed together and a solid is formed is a precipitation reaction. To find the mass of Ca3(PO4)2 needed, we can multiply the number of moles by the molar mass:Ġ.0270 mol Ca3(PO4)2 x 310.18 g/mol = 8.37 g Ca3(PO4)2 We can do this by dividing the mass by the molar mass of CaSiO3:Ĥ.30 g / (40.08 g/mol + 28.09 g/mol + 159.69 g/mol) = 0.0135 mol CaSiO3įinally, we can use the mole ratio to find the number of moles of Ca3(PO4)2 needed:Ģ moles Ca3(PO4)2 / 1 mole CaSiO3 = x moles Ca3(PO4)2 / 0.0135 mol CaSiO3 Next, we need to find the number of moles of CaSiO3 in 4.30 g. Therefore, the mole ratio between Ca3(PO4)2 and CaSiO3 is 2:1 (2 moles of Ca3(PO4)2 for every 1 mole of CaSiO3). From the balanced equation, we can see that 6 moles of Ca3(PO4)2 react with 6 moles of SiO2 to form 6 moles of CaSiO3. First, we need to find the mole ratio between Ca3(PO4)2 and CaSiO3. Ca3(PO4)2 + 6 SiO2 -> P4O10 + 6 CaSiO3ġa) To find the grams of Ca3(PO4)2 needed to form 4.30 g of CaSiO3, we need to use stoichiometry. Order the following compounds and ions from 1 = the lowest oxidation state of S to 4 = the highest:Ģ. The correct way to write Na3PO4(aq) in a complete ionic equation is 3Na+(aq) + PO4-3(aq).ģ. We do NOT split H2O(l) in a complete ionic equation because it's not aqueous.į. The oxidation state of oxygen in Na3PO4 is -2.Į. When Ca3(PO4)2 is formed during a precipitation reaction, it forms as a solid because it's insoluble in water.ĭ. If an atom gets oxidized during a reaction, the compound that contains that atom at the beginning of the reaction is the reducing agent.Ĭ. One product of the reaction between Na3PO4 (aq) and CaCl2(aq) is Na3Cl2(aq).ī. Click on each correct statement below dealing with reactions happening in aqueous solution. An acid-base reaction can be recognized because an acid is a compound that produces H+ ions in water and a base is a compound that produces OH- ions.Ģ. A reaction in which one or more electrons are transferred from one atom to another is a(n) redox reaction. Ca3(PO4)2 + 6 SiO2 –> P4O10 + 6 CaSiO3Ī) How many grams of Ca3(PO4)2 would be needed to form 4.30 g of CaSiO3?Ī reaction in which two solutions are mixed together and a solid is formed is a(n) precipitation reaction.
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